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Question

The vapour density of a mixture containing NO2 and N2O4 is 27.6. The mole fraction of NO2 in the mixture will be :

A
0.2
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B
0.4
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C
0.6
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D
0.8
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Solution

The correct option is D 0.8
The equilibrium reaction is N2O4(g)2NO2(g).
Initially, 1 mole of N2O4 and 0 moles of NO2 are present.
At equilibrium, 1α moles of N2O4 and 2α moles of NO2 are present. Here, α is the degree of dissociation of N2O4.
The relationship between the degree of dissociation α, the molecular weight D of NO2 and the vapour density d is as shown below.
α=Dd(n1)d=4627.627.6=0.67
The mole fraction of NO2=2α1+α=0.80.

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