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Molality

The vapour de...

Question

The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27^°C. Calculate the mole no of NO2 in 100g mixture.

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Solution

$M_{a v g} = 2 \times V a p o r d e n s i t y = 76.6$
$L e t t h e n u m b e r o f m o l e s o f {N O}_{2} b e x$
$T h e m o l e o f N_{2} O_{4} = 100 - x$
$M_{a v g} = n_{N O_{2}} M_{{N O}_{2}} + n_{N_{2} O_{4}} \times M_{N_{2} O_{4}}$
$76.6 = \frac{x \times 46 + (100 - x) \times 92}{100}$
$7660 = 46 x + 9200 - 92 x$
$46 x = 1540$
$x = 33.48 m o l e s$
$M o l e s o f {N O}_{2} i n 100 m o l e s o f t h e m i x t u r e = 33.4$

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