Question

The volume of 0.1 M oxalic acid that can be completely oxidized by 20 ml of 0.025 M $KMn{O}_4$ solution is :

• A. 125 ml
• B. 25 ml
• C. 12.5 ml
• D. 37.5 ml

Answer 1

The correct option is C 12.5 ml

$2KMn{O}_4+5H_2{C}_2{O}_4+6H^{+}\to 2K^{+}+2M{n}^{2+}+10C{O}_2+8H_{2}O$

$\frac{M_{KMn{O}_4}{V}_{KMn{O}_4}}{2}=\frac{M_{H_2{C}_2{O}_4}{V}_{H_2{C}_2{O}_4}}{5}$

$\frac{0.025M\times 20ml}{2}=\frac{0.1M\times V_{H2C2O4}}{5}$

$V_{H_2{C}_2{O}_4}=12.5ml$

The volume of 0.1 M oxalic acid that can be completely oxidized by 20 ml of 0.025 M $KMn{O}_4$ solution is $12.5ml$.