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Question

The volume of 2.8 g of carbon monoxide at 27oC and 0.821atm pressure is:

A
0.03 L
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B
3 L
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C
0.3 L
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D
1.5 L
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Solution

The correct option is D 3 L
The volume of carbon monoxide=nRTP
Mass of carbon\quad monoxide=2.8g
P=0.821 atm,
T=27+273=300K
R=0.0821
because gram molecular weight of CO=12+16=28
because number of moles in 2.8g of CO=2.828=0.1
therefore volume=0.1×0.0821×3000.821=3 litre

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