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Standard XII

Chemistry

Derivation of Kp and Kc

The volume of...

Question

The volume of $H C l$ passed through the solution at $25^{o} C$ and $1$ atm is:

24.46 m L

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2.446 m L

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244.6 m L

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0.2446 m L

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Solution

The correct option is A $24.46 m L$
$p H$ of solution after passage of $H C l = 3$

$∴$ $[H^{+}] = 10^{- 3} M$ or $[H C l] = 10^{- 3} M$

From $P V = n R T$

$1 \times V = 10^{- 3} \times 0.0821 \times 298$

$V = 24.46 \times 10^{- 3} L = 24.46 m L$

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The volume of HCl passed through the solution at 25oC and 1 atm is:

The correct option is A 24.46mLpH of solution after passage of HCl=3∴ [H+]=10−3M or [HCl]=10−3MFrom PV=nRT1×V=10−3×0.0821×298V=24.46×10−3L=24.46mL

The volume of $H C l$ passed through the solution at $25^{o} C$ and $1$ atm is:

The correct option is A $24.46 m L$
$p H$ of solution after passage of $H C l = 3$

$∴$ $[H^{+}] = 10^{- 3} M$ or $[H C l] = 10^{- 3} M$

From $P V = n R T$

$1 \times V = 10^{- 3} \times 0.0821 \times 298$

$V = 24.46 \times 10^{- 3} L = 24.46 m L$