Question

The volume of water to be added to 200 mL of seminormal $HCl$ solution to make it decinormal is:

• A. 200 mL
• B. 400 mL
• C. 600 mL
• D. 800 mL

Answer 1

The correct option is D 800 mL

$n_{factor}$ of $HCl=1$

Seminormal $=0.5N,Volume=200$ $mL,Decinormal=\frac{N}{10}=0.1$

$N_1{V}_1=N_2{V}_2$

$\therefore 200\times 0.5=0.1\times V$

$\therefore V=\frac{200\times 0.5}{0.1}=1000$

Volume required to make decinormal solution $=1$ $Litre=1000$ $mL$

So, volume added to $200$ $mL$ solution $=1000-200=800$ $mL$

Hence, option $D$ is correct.