The weight of any person on the moon is about $\frac{1}{6}$ times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

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Solution

$g_{e} = g$ and $g_{m} = \frac{g}{6}$

Force applied to life a mass of 15 kg at the earth, $F = m g_{e} = 15 g_{e} N$
Therefore, the mass lifted by the same force on the moon.
$F = m g_{m}$
$m = \frac{F}{g_{m}} = \frac{15 g_{e}}{g_{m}} = \frac{15 g}{\frac{g}{6}} = 90 k g$

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Universal Law of Gravitation

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The weight of any person on the moon is about 16 times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

ge=g and gm=g6 Force applied to life a mass of 15 kg at the earth, F=mge=15geN Therefore, the mass lifted by the same force on the moon. F=mgm m=Fgm=15 gegm=15 gg6=90 kg

The weight of any person on the moon is about $\frac{1}{6}$ times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

$g_{e} = g$ and $g_{m} = \frac{g}{6}$

Force applied to life a mass of 15 kg at the earth, $F = m g_{e} = 15 g_{e} N$
Therefore, the mass lifted by the same force on the moon.
$F = m g_{m}$
$m = \frac{F}{g_{m}} = \frac{15 g_{e}}{g_{m}} = \frac{15 g}{\frac{g}{6}} = 90 k g$