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Byju's Answer

Standard XII

Physics

Analysis of Force Equation

The work done...

Question

The work done by a magnetic field, on a moving charge is

zero because

\to F

acts parallel to

\to v

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positive because

\to F

acts perpendicular to

\to v

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zero because

\to F

acts perpendicular to

\to v

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negative because

\to F

acts parallel to

\to v

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Solution

The correct option is A zero because $\to F$ acts perpendicular to $\to v$
Force on moving charge while moving in magnetic field is;
$\to = q (\to v \times \to B)$
where $\to F$ is perpendicular to $\to v$ .
Work done/sec $= \to F . \to v = F \to v c o s 90^{o} = 0$

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The work done by a magnetic field, on a moving charge is

The correct option is A zero because →F acts perpendicular to →vForce on moving charge while moving in magnetic field is; →=q(→v×→B) where →F is perpendicular to →v. Work done/sec =→F.→v=F→vcos90o=0

The correct option is A zero because $\to F$ acts perpendicular to $\to v$
Force on moving charge while moving in magnetic field is;
$\to = q (\to v \times \to B)$
where $\to F$ is perpendicular to $\to v$ .
Work done/sec $= \to F . \to v = F \to v c o s 90^{o} = 0$