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Work Done, Varying Force and Path

The work done...

Question

The work done in joules in increasing the extension of a spring of stiffness 10 N/cm from 4 cm to 6 cm is:

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100

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Solution

The correct option is A 1
Work done $W = \frac{1}{2} k (X_{2}^{2} - X_{1}^{2})$
$= \frac{1}{2} 10 (6^{2} - 4^{2}) = 100 N c m = 1 j o u l e .$

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