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Question

# There are 200 packets in a large box and each packet contains 3 electric devices in it. On testing, at the time of packing, it was noted that there are some faulty pieces in the packets. The data is as below No of faulty devices in a packetLess than2424−3636−48morethan48TotalBatteriesNumber of batteries502405501601000 (i) If a buyer will only tolerate atthe maximum one faulty piece in a packet, what is the probability that a packet will be rejected? (ii) Another buyer will only take packets with all the pieces functional. What is the probability that a packet will be rejected? [4 MARKS]

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Solution

## Concept: I Mark Solution: 1.5 Marks each Packets with more than one defective piece = 15 + 5 = 20 (i) Probability that the first buyer will reject a packet = 20/200 = 0.1 Packets with at least one piece that is defective = 15 + 5 + 25 = 45 (ii) Probability that the second buyer will reject a packet = 45/200 = 0.225

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