Question

There are 6 red and 5 black balls in a bag. Two balls are drawn at random one after another with replacement. The probability that both the balls drawn may be black is

• A. $\frac{30}{121}$
• B. $\frac{25}{121}$
• C. $\frac{36}{121}$
• D. $\frac{36}{221}$

Answer 1

The correct option is B $\frac{25}{121}$

A bag contains: $6R+5B=11$
Probability of getting $1B+1B$ ball from this bag with replacement:
$=\left(\frac{5}{11}\right)\times \left(\frac{5}{11}\right)=\frac{25}{121}$