There are 600 electric bulbs in a box, out of which 20 bulbs are defective. If one bulb is chosen at random from the box, what is the probability that it is defective?
(a) $\frac{1}{19}$

(b) $\frac{1}{20}$

(c) $\frac{1}{30}$

(d) $\frac{29}{30}$

Open in App

Solution

(c) $\frac{1}{30}$

Explanation:
Total number of bulbs in the box = 600
Number of defective bulbs = 20
Let E be the event that the chosen bulb is defective.

∴ Required probability = P(E) = $\frac{20}{600} = \frac{1}{30}$

Suggest Corrections

Similar questions

Q. There are 600 electric bulbs in a box, out of which 20 bulbs are defective. If one bulb is chosen at random from the box, what is the probability that it is defective?
(a)

\frac{1}{19}

(b)

\frac{1}{20}

(c)

\frac{1}{30}

(d)

\frac{29}{30}

Q. A box contains

20

electric bulbs, out of which

4

are defective. One bulb is chosen at random from this box. The probability of getting a defective bulb is ___________.

It is known that a box of 600 electric bulbs contains 12 defective bulbs. One bulb is taken out at random from this box. What is the probability that it is a non-defective bulb?

Q. A bulb is taken out at random from a box of 600 electric bulbs that contains 12 defective bulbs. Then the probability of a non-defective bulb is

It is known that a box of 100 electric bulbs contains 8 defeective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective ? (ii) non-defective?

Join BYJU'S Learning Program

There are 600 electric bulbs in a box, out of which 20 bulbs are defective. If one bulb is chosen at random from the box, what is the probability that it is defective? (a) 119 (b) 120 (c) 130 (d) 2930

(c) 130Explanation:Total number of bulbs in the box = 600 Number of defective bulbs = 20 Let E be the event that the chosen bulb is defective. ∴ Required probability = P(E) = 20600 = 130

There are 600 electric bulbs in a box, out of which 20 bulbs are defective. If one bulb is chosen at random from the box, what is the probability that it is defective?
(a) $\frac{1}{19}$

(b) $\frac{1}{20}$

(c) $\frac{1}{30}$

(d) $\frac{29}{30}$

(c) $\frac{1}{30}$

Explanation:
Total number of bulbs in the box = 600
Number of defective bulbs = 20
Let E be the event that the chosen bulb is defective.

∴ Required probability = P(E) = $\frac{20}{600} = \frac{1}{30}$