Three atoms of magnesium combine with $2$ atoms of nitrogen. What will be the weight of magnesium which combines with $1.86 g$ of nitrogen?

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Solution

Reaction :

$3 M g + N_{2} \to M g_{3} N_{2}$

According to the above reaction, 1 mole of Nitrogen gas combine with 3 moles of Magnesium or 28gm of $N_{2}$ combines with 72 gm of $M g$ .

$⟹ 1 g m o f N_{2}$ combine with $\frac{72}{28} g m o f M g$

$⟹ 1.86 g m o f N_{2}$ combine with $\frac{72}{28} \times 1.86 g m o f M g$

$⟹ 1 g m o f N_{2}$ combine with $4.78 g m o f M g$

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Three atoms of magnesium combine with 2 atoms of nitrogen. What will be the weight of magnesium which combines with 1.86 g of nitrogen?

Reaction :3Mg+N2→Mg3N2According to the above reaction, 1 mole of Nitrogen gas combine with 3 moles of Magnesium or 28gm of N2 combines with 72 gm of Mg.⟹1 gm of N2 combine with 7228gm of Mg⟹1.86 gm of N2 combine with 7228×1.86 gm of Mg⟹1 gm of N2 combine with 4.78 gm of Mg

Three atoms of magnesium combine with $2$ atoms of nitrogen. What will be the weight of magnesium which combines with $1.86 g$ of nitrogen?