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Question

Three capacitors of capacities 8μF,8μF, and 4μF are connected in series and a potential difference of 120 volt is maintained across the combination. Calculate the charge on capacitor of capacity 4μF.

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Solution

Series connection :
Equivalent capacitance 1Ceq=18+18+14
Ceq=2 μF
Charge flown through the circuit Q=CeqV=2μF×120=240 μC
In series connection, all the capacitors have same charge. So, charge on 4μF capacitor is 240 μC

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