The correct option is B S1
According to the Gauss's law the flux of the electric field through closed surface is
ϕ=qenε0
Where, qen is the charge enclosed by the closed surface.
So, the flux will be maximum for that surface, which incloses maximum charge.
Charge enclosed by surface S1,
QS1=q1+q2
⇒QS1=1×10−6+2×10−6
⇒QS1=3×10−6 C
Charge enclosed by surface S2,
QS2=q2+q3
⇒QS2=2×10−6−3×10−6
⇒QS2=−1×10−6 C
Charge enclosed by surface S3,
QS3=q1+q2+q3
⇒QS3=1×10−6+2×10−6−3×10−6
⇒QS3=0
So, the charge enclosed is maximum across S1
So, flux will be maximum across S1.
Hence, option (a) is correct asnwer.