Question

Three coins are tossed simultaneously. What is the probability of getting at least two heads?

Answer 1

When 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.
Total number of possible outcomes = 8

Let E be the event of getting at least two heads.

Then, the favourable outcomes are HHH, HHT, THH, and HTH.
​Number of favourable outcomes = 4

∴ P(getting at least 2 heads) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{favo}\text{u}\mathrm{rable}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{outcomes}}=\frac{4}{8}=\frac{1}{2}$