Three consecutive integers are such that four times the smallest is three times the largest. Find the largest integer.

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Solution

The correct option is B $8$
Let the three consecutive integers be $x, (x + 1), (x + 2)$
As per the problem, we have
$4 x = 3 (x + 2)$
$∴ 4 x = 3 x + 6$
$∴ 4 x - 3 x = 6$
$∴ x = 6$
Largest integer will be $(x + 2) = 6 + 2 = 8$

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Three consecutive integers are such that four times the smallest is three times the largest. Find the largest integer.

The correct option is B 8Let the three consecutive integers be x,(x+1),(x+2)As per the problem, we have4x=3(x+2)∴4x=3x+6∴4x−3x=6∴x=6Largest integer will be (x+2)=6+2=8

The correct option is B $8$
Let the three consecutive integers be $x, (x + 1), (x + 2)$
As per the problem, we have
$4 x = 3 (x + 2)$
$∴ 4 x = 3 x + 6$
$∴ 4 x - 3 x = 6$
$∴ x = 6$
Largest integer will be $(x + 2) = 6 + 2 = 8$