Three consecutive integers are such that when they are taken in increasing order and multiplied by $2, 3 a n d 4$ respectively, they add up to $74$ . Find these numbers.

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Solution

Let the three consecutive integers be $x - 1, x, x + 1$ .
$2 (x - 1) + 3 x + 4 (x + 1) = 74$
$2 x - 2 + 3 x + 4 x + 4 = 74$
$9 x = 72$
$x = 8$
So the numbers are $7, 8, a n d 9 .$

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Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3and4respectively, they add up to 74. Find these numbers.

Let the three consecutive integers be x-1,x,x+1.2(x-1)+3x+4(x+1)=742x–2+3x+4x+4=749x=72x=8So the numbers are 7,8,and9.

Three consecutive integers are such that when they are taken in increasing order and multiplied by $2, 3 a n d 4$ respectively, they add up to $74$ . Find these numbers.

Let the three consecutive integers be $x - 1, x, x + 1$ .
$2 (x - 1) + 3 x + 4 (x + 1) = 74$
$2 x - 2 + 3 x + 4 x + 4 = 74$
$9 x = 72$
$x = 8$
So the numbers are $7, 8, a n d 9 .$