Three consecutive odd integers are such that when they are taken in increasing order and multiplied by 3, 4 and 5 respectively, they add up to 112. Find these numbers. [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

Let three consecutive odd numbers 2n + 1, 2n + 3, 2n + 5

3(2n + 1)+ 4(2n + 3) + 5(2n + 5) = 112

6n + 3 + 8n + 12 + 10n + 25 = 112

24n + 40 = 112

24n = 72

n = 3

Numbers are 7, 9, 11

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Three consecutive odd integers are such that when they are taken in increasing order and multiplied by 3, 4 and 5 respectively, they add up to 112. Find these numbers. [2 MARKS]

Concept: 1 Mark Application: 1 Mark Let three consecutive odd numbers 2n + 1, 2n + 3, 2n + 5 3(2n + 1)+ 4(2n + 3) + 5(2n + 5) = 112 6n + 3 + 8n + 12 + 10n + 25 = 112 24n + 40 = 112 24n = 72 n = 3 Numbers are 7, 9, 11

Concept: 1 Mark
Application: 1 Mark

Let three consecutive odd numbers 2n + 1, 2n + 3, 2n + 5

3(2n + 1)+ 4(2n + 3) + 5(2n + 5) = 112

6n + 3 + 8n + 12 + 10n + 25 = 112

24n + 40 = 112

24n = 72

n = 3

Numbers are 7, 9, 11