Question

Three symmetrical dice are thrown. The probability that the same number will appear on each of them is:

• A. $\frac{1}{216}$
• B. $\frac{1}{36}$
• C. $\frac{35}{36}$
• D. $\frac{1}{35}$

Answer 1

The correct option is B $\frac{1}{36}$

When three symmetrical dice thrown, total cases will be $=6\times 6\times 6$
Cases when same number will appear on each of them: $(1,1,1),(2,2,2),(3,3,3),(4,4,4),(5,5,5),(6,6,6)$ $=6$ cases
Probability when same number will appear on each of them $=\frac{6}{6\times 6\times 6}=\frac{1}{36}$