"Three times $x$ added to the cube of $y$ " is

$3 (x + y^{3})$

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$3 x y^{3}$

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$3 x + y^{3}$

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$3 (x + 3 y)$

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Solution

The correct option is C
$3 x + y^{3}$

Three times $x$ = $3 x$
Cube of $y$ = $y^{3}$
Now, the sum of Three times $x$ and the cube of $y$ = $3 x + y^{3}$
Hence, the answer is $3 x + y^{3}$

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What should be added to $x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3}$ to get $x^{3} + y^{3} ?$

Three times $x$ added to two times $y$ is written as :

Twelve added to three times a number is equal to three added to four times a number. Find the number.

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