Tick (✓) the correct answer:
A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in
(a) 24 days
(b) 27 days
(c) 36 days
(d) 48 days

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Solution

(c) 36 days

$Let A take x days to complete the work . Then B takes 2 x days to complete the work . A' s 1 day' s work = \frac{1}{x} B' s 1 day' s work = \frac{1}{2 x} A and B take 12 days to complete the work . Net work done by (A + B) in 1 day = \frac{1}{12} = \frac{1}{x} + \frac{1}{2 x} = \frac{3}{2 x} \Rightarrow 2 x = 36 \Rightarrow x = 18 A can complete the work by himself in 18 days . B will take 36 days, i . e ., twice as long as the time taken by A .$

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A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in

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Q. Mark (✓) against the correct answer:
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(a) 24 hours
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(c) 36 hours
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A can do a piece of work in 15 days. B is 50% more efficient than A. B can finish the total work in
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Tick (✓) the correct answer: A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in (a) 24 days (b) 27 days (c) 36 days (d) 48 days

Tick (✓) the correct answer:
A works twice as fast as B. If both of them can together finish a piece of work in 12 days, then B alone can do it in
(a) 24 days
(b) 27 days
(c) 36 days
(d) 48 days