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Molecular Orbitals of Carbon

to account fo...

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to account for atomic mass of nitrogen as 14.0067 what should be the ratio of 15^N and 14^N atoms in natural nitrogen. (atomic mass of 14^N = 14.00307 u, 15^N=15.001 u) .

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Q. The nucleodic masses of

^{14} N

^{15} N

are mixed to give atomic mass of 14.1. What is the ratio of the two isotopes as a whole number.

Q. What will be the ratio of

^{15} N /^{15} N :^{15} N /^{14} N :^{14} N /^{14} N

D N A s

, if Meselson and Stahl experiment is continued for four generations in

E . c o i l

Q. If Meselson and Stahl's experiment is continued for 4 generations in E. coli, then the ratio of

^{15} N

^{15} N

^{15} N

^{14} N

^{14} N

^{14} N

in the end would be:

Q. Meselson and Stahl's experiment is continued for three generations in bacteria. The ratio of

^{15} N /^{15} N :^{15} N /^{14} N :^{14} N /^{14} N

containing DNA in the third generation would be

Q. Natural nitrogen is 99.63%

^{14} N

with mass 14.00307 amu and 0.37%

^{15} N

, with mass number 15.00011 amu. Which isotope is more stable,

^{14} N

^{15} N

?
Plan Binding energy per nucleon

= \frac{△ m (a m u) \times 931}{n u m b e r o f n u c l e o n s}

Isotope with larger binding energy per nucleon is more stable.

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