To win an election- a candidate needs 3-4 th of the votes cast- If after 2-3rd of the votes have been counted- a candidate has 5-6th of what he needs- then what part of the remaining votes does he still he need-

The correct option is D (3/8) Let the total votes cast = x Votes counted = 2/3x Votes uncounted = 1/3x Remaining votes the candidate needs = 1/6×3/4x = 1/8x ∴ ...

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To win an ele...

Question

To win an election, a candidate needs ${\frac{3}{4}}^{t h}$ of the votes cast. If after ${\frac{2}{3}}^{r d}$ of the votes have been counted, a candidate has ${\frac{5}{6}}^{t h}$ of what he needs, then what part of the remaining votes does he still he need?

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Solution

The correct option is D
(3/8)

Let the total votes cast = $x$

Votes counted = $\frac{2}{3} x$

Votes uncounted = $\frac{1}{3} x$

Remaining votes the candidate needs = $\frac{1}{6} \times \frac{3}{4} x$ = $\frac{1}{8} x$

$∴$ Required part = $\frac{\frac{1}{8} x}{\frac{1}{3} x}$ = $\frac{3}{8}$

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To win an election, a candidate needs 34th of the votes cast. If after 23rd of the votes have been counted, a candidate has 56th of what he needs, then what part of the remaining votes does he still he need?

The correct option is D (3/8) Let the total votes cast = x Votes counted = 23x Votes uncounted = 13x Remaining votes the candidate needs = 16×34x = 18x ∴ Required part = 18x13x = 38

To win an election, a candidate needs ${\frac{3}{4}}^{t h}$ of the votes cast. If after ${\frac{2}{3}}^{r d}$ of the votes have been counted, a candidate has ${\frac{5}{6}}^{t h}$ of what he needs, then what part of the remaining votes does he still he need?

The correct option is D
(3/8)

Let the total votes cast = $x$

Votes counted = $\frac{2}{3} x$

Votes uncounted = $\frac{1}{3} x$

Remaining votes the candidate needs = $\frac{1}{6} \times \frac{3}{4} x$ = $\frac{1}{8} x$

$∴$ Required part = $\frac{\frac{1}{8} x}{\frac{1}{3} x}$ = $\frac{3}{8}$