Torque applied on a particle is zero, then, its angular momentum will be

Equal in direction

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Equal in magnitude

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Both (a) and (b)

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Data Insufficient

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Solution

The correct option is C Both (a) and (b)
Torque $τ = \frac{d L}{d t}$
When, $τ = 0$ , then L= constant
Which means that L remains constant in magnitude as well as direction.

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Torque applied on a particle is zero, then, its angular momentum will be

The correct option is C Both (a) and (b)Torque τ=dLdtWhen, τ=0, then L= constant Which means that L remains constant in magnitude as well as direction.

The correct option is C Both (a) and (b)
Torque $τ = \frac{d L}{d t}$
When, $τ = 0$ , then L= constant
Which means that L remains constant in magnitude as well as direction.