Total vapour pressure of mixture of $1$ mol X( $P^{o}_{X} = 150 t o r r)$ and 2 mol $Y$ ( $P^{0}_{Y} = 300 t o r r$ ) is $240$ torr. In this case:

there is a negative deviation from Raoult's law

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there is positive deviation from Raoult's law

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there is no deviation from Rault's law

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cannot be decided

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Solution

The correct option is A there is a negative deviation from Raoult's law
There is a negative deviation from Raouelt's law
because, when vapour pressure of a mixture is lower than it turns out to be negative deviation

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Total vapour pressure of mixture of 1 mol X( PoX=150 torr) and 2 mol Y (P0Y=300torr) is 240 torr. In this case:

The correct option is A there is a negative deviation from Raoult's lawThere is a negative deviation from Raouelt's lawbecause, when vapour pressure of a mixture is lower than it turns out to be negative deviation

Total vapour pressure of mixture of $1$ mol X( $P^{o}_{X} = 150 t o r r)$ and 2 mol $Y$ ( $P^{0}_{Y} = 300 t o r r$ ) is $240$ torr. In this case:

The correct option is A there is a negative deviation from Raoult's law
There is a negative deviation from Raouelt's law
because, when vapour pressure of a mixture is lower than it turns out to be negative deviation