Twenty counters are placed in a bag. Eight of them are red, six are yellow, four are green and the remaining blue. If one counter is picked at random, what is the probability that it is green?

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Solution

Step 1 Finding the probability that the counter is green:
The event is selecting a counter at random.
There are $20$ counters placed in a bag.
So, the total number of outcomes is $20$ .
Out of the total counters, $8$ are red, $6$ are yellow, $4$ are green and the remaining are blue.
There are $4$ green counters in the bag.
So, the number of favourable outcomes is $4$ .
The formula for probability is,
$\Rightarrow P r o b a b i l i t y = \frac{N u m b e r o f f a v o u r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s} \Rightarrow P (g r e e n) = \frac{4}{20} ∴ P (g r e e n) = \frac{1}{5}$
Therefore, the probability of green counters is $\frac{1}{5}$ .

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