Twice a number minus three times another is equal to $2$ . The sum of these numbers is $11$ . The difference of these numbers is

2

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Solution

The correct option is C $3$
$2 x - 3 y = 2$
$(x + y = 11) 2$
$2 x + 2 y = 22$
$+ 2 x - 3 y = 2$
$(-) (+) (-) - ---------- -$
$5 y = 20$
or $y = 4$
$∴ x = 11 - 4$
or $x = 7$
Hence, $x - y = 7 - 4 = 3$ .

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Q. Rewrite the following using a letter.
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Twice a number minus three times another is equal to 2. The sum of these numbers is 11. The difference of these numbers is

The correct option is C 32x−3y=2(x+y=11)22x+2y=22+2x−3y=2(−)(+)(−)––––––––––––5y=20or y=4∴x=11−4or x=7Hence, x−y=7−4=3.

Twice a number minus three times another is equal to $2$ . The sum of these numbers is $11$ . The difference of these numbers is

The correct option is C $3$
$2 x - 3 y = 2$
$(x + y = 11) 2$
$2 x + 2 y = 22$
$+ 2 x - 3 y = 2$
$(-) (+) (-) - ---------- -$
$5 y = 20$
or $y = 4$
$∴ x = 11 - 4$
or $x = 7$
Hence, $x - y = 7 - 4 = 3$ .