Question

Twice the difference of a number and $1$is $4$more than that number

Answer 1

Solve the equation

Let, the number be $x$

From the given condition,

$$\begin{gathered} \Rightarrow 2(x-1)=x+4 \\ \Rightarrow 2x-2=x+4 \end{gathered}$$

Adding $2$ to both sides of the equation, we get

$$\begin{gathered} \Rightarrow 2x-2+2=x+4+2 \\ \Rightarrow 2x=x+6 \end{gathered}$$

Subtracting $x$ from both the sides, we get

$$\begin{gathered} \Rightarrow 2x-x=x+6-x \\ \Rightarrow x=6 \end{gathered}$$

Hence, the required number is $6$