Question

Two capacitors of capacitances $8\mu \text{F}$ and $16\mu \text{F}$ in parallel are connected to a battery of $1\text{V}$. Find the ratio of charge stored in $8\mu \text{F}$ capacitor to the charge stored in $16\mu \text{F}$

• A. $\frac{2}{3}$
  
• B. $\frac{1}{3}$
  
• C. $\frac{1}{2}$
  
• D. $\frac{3}{2}$
  

Answer 1

The correct option is C $\frac{1}{2}$


The capacitors are in parallel, which implies that the potential difference across both the capacitors will be $1\text{V}$.

Now, the charge on $8\mu \text{F}$ capacitor, $Q_1=8\times 1=8\mu \text{C}$

The charge on $16\mu \text{F}$ capacitor, $Q_2=16\times 1=16\mu \text{C}$

So, $\frac{Q_1}{Q_2}=\frac{1}{2}$

Why this Question ? In parallel combination of capacitors, the potential difference across the capacitors remains same, however, the charges are different.