Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is 2/3 to the height in capillary Q. The ratio of their diameters is

2 : 3

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3 : 2

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3 : 4

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4 : 3

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Solution

The correct option is B
3 : 2

$r \propto \frac{1}{h} \Rightarrow \frac{r_{P}}{r_{Q}} = \frac{h_{Q}}{h_{P}} = \frac{h}{\frac{2}{3} h} = \frac{3}{2}$

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Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is 2/3 to the height in capillary Q. The ratio of their diameters is

The correct option is B 3 : 2 r∝1h⇒rPrQ=hQhP=h23h=32

The correct option is B
3 : 2

$r \propto \frac{1}{h} \Rightarrow \frac{r_{P}}{r_{Q}} = \frac{h_{Q}}{h_{P}} = \frac{h}{\frac{2}{3} h} = \frac{3}{2}$