Two cars A and B cross a point P with velocities 10/m and 15 m/s. After that, they move with different uniform accelerations and the car A overtakes B with a speed of 25 ms^-1. What is velocity of B at that instant?

20 ms^-1

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25 ms^-1

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30 ms^-1

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40 ms^-1

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Solution

The correct option is A 20 ms^-1
Let a_A = a₁ and a_B =a₂

(25)² = (10)² + 2a₁S

Or 2a₁S = 525S

25 = 10 + a_1t

∴ a₁t = 15

Let velocity of B at that instant is v. Then

V² = (15)² + 2a₁S

Or 2a₁s = v²-225

V = 15 + a₂t

∴ a₂t = v - 15

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