Two charges placed in air repel each other by a force of $10^{N} N .$ When oil is introduced between the charges, the force becomes $2.5 \times 10^{- 5} N$ . The dielectric constant of oil is

2.5

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0.25

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2.0

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4.0

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Solution

The correct option is D
4.0

By using $K = \frac{F_{a}}{F_{m}} \Rightarrow K = \frac{10^{- 4}}{2.5 \times 10^{- 5}} = 4$

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Two charges placed in air repel each other by a force of 10NN. When oil is introduced between the charges, the force becomes 2.5×10−5N. The dielectric constant of oil is

The correct option is D 4.0 By using K=FaFm⇒K=10−42.5×10−5=4

Two charges placed in air repel each other by a force of $10^{N} N .$ When oil is introduced between the charges, the force becomes $2.5 \times 10^{- 5} N$ . The dielectric constant of oil is

The correct option is D
4.0

By using $K = \frac{F_{a}}{F_{m}} \Rightarrow K = \frac{10^{- 4}}{2.5 \times 10^{- 5}} = 4$