Question

Two dice are thrown simultaneously $500$ times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table.

Sum	Frequency
2	14
3	30
4	42
5	55
6	72
7	75
8	70
9	53
10	46
11	28
12	15

What is the probability of getting a sum $3$?

Answer 1

Two dice are thrown $500$ times. So, the total number of trials are $500$.

Let $E_1$ be the event that sum of two numbers appearing on the uppermost faces of two dice be $3$. Number of time in which the event happend is $30$.

$\therefore P\left(E_1\right)=\frac{Numberoftrailsinwhichtheeventhapped}{Totalnumberoftrails}$

$=\frac{30}{500}=\frac{3}{50}=0.06$