Question

Two dice are thrown simultaneously. The probability of getting the sum equal to an odd number is

• A.
  1
• B.
  0
• C.
  $\frac{1}{2}$
• D.
  $\frac{1}{3}$

Answer 1

The correct option is C

$\frac{1}{2}$
When two dice are thrown simultaneously, the total number of possible outcomes is $6^2=36.$

Let A be the event of getting a sum of outcomes as an odd number.

Thus, the favourable outcomes are $(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5).$

Thus, the number of favourable outcomes is 18.

$\therefore P\left(A\right)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}=\frac{18}{36}=\frac{1}{2}$



Hence, the correct answer is option c.