Question

Two electric bulbs have resistances in the ratio 1 : 2. If they are joined in series, the energy consumed in these are in the ratio ................

• A. 1 : 2
• B. 2 : 1
• C. 4 : 1
• D. 1 : 1

Answer 1

The correct option is A 1 : 2

$P=I^{2}R$

When two resistances are connected in series, current through them is same.

Hence, $\frac{P_1}{P_2}=\frac{R_1}{R_2}=\frac{1}{2}$

Answer-(A)