Question

Two electric bulbs whose resistance are in the ratio of $1:2$ are connected in parallel to a constant voltage source. The ratio of the power dissipated in them will be:

• A. $1:4$
• B. $1:2$
• C. $1:1$
• D. $2:1$

Answer 1

The correct option is D $2:1$

Given : $\frac{R_1}{R_2}=\frac{1}{2}$

And, the voltage difference across the resistors is the same in parallel connection.

And, $P=\frac{V^2}{R}$

Ratio of power dissipated $\frac{P_1}{P_2}=\frac{V^2/R_1}{V^2/R_2}=\frac{R_2}{R_1}=2$