Question

Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio

• A. 1 : 2
• B. 1 : 1
• C. 2 : 1
• D. 1 : 4

Answer 1

The correct option is C 2 : 1

Power dissipated $=\frac{E^2}{R}$

$\frac{P_1}{P_2}=\frac{\frac{E^2}{R_1}}{\frac{E^2}{R_2}}=\frac{R_2}{R_1}$

$Given\frac{R_1}{R_2}=\frac{1}{2}$

$\frac{P_1}{P_2}=\frac{2}{1}$