Question

Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected to a constant voltage source. If the two bulbs are connected in series, the power dissipated in them have the ratio

• A. 1 : 2
• B. 1 : 1
• C. 2 : 1
• D. 1 : 4

Answer 1

The correct option is A 1 : 2

$P=I^{2}R$
$\frac{P_1}{P_2}=\frac{I^2{R}_1}{I^2{R}_2}$
$=\frac{R_1}{R_2}=1/2$