Two equal poles repel each other with a force of 10 $^{- 3}$ N. When placed 2cm apart in air, the pole strength of each is (in amp-m).

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Solution

The correct option is B 2
$F = 10^{- 3} N$
$d = 2 c m$
$m_{1} = m_{2} = m$
$F = \frac{μ_{0} m_{1} m_{2}}{4 π d^{2}}$
$10^{- 3} = \frac{10^{- 7} \times m^{2}}{(2 \times 10^{- 2})^{2}}$
$m = 2 A m$

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Two equal poles repel each other with a force of 10−3 N. When placed 2cm apart in air, the pole strength of each is (in amp-m).

The correct option is B 2F=10−3Nd=2cmm1=m2=mF=μ0m1m24πd210−3=10−7×m2(2×10−2)2m=2Am

Two equal poles repel each other with a force of 10 $^{- 3}$ N. When placed 2cm apart in air, the pole strength of each is (in amp-m).

The correct option is B 2
$F = 10^{- 3} N$
$d = 2 c m$
$m_{1} = m_{2} = m$
$F = \frac{μ_{0} m_{1} m_{2}}{4 π d^{2}}$
$10^{- 3} = \frac{10^{- 7} \times m^{2}}{(2 \times 10^{- 2})^{2}}$
$m = 2 A m$