Two equipotential surfaces of $40 V$ and $50 V$ potential are separated by $2 c m$ . If the electric field present between them is uniform, then its strength is :

200 V / m

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1000 V / m

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400 V / m

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500 V / m

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Solution

The correct option is D $500 V / m$
For the uniform electric field , $Δ V = E d$ where $Δ V = 50 - 40 = 10$ V is potential difference between the two equipotential surfaces.
thus, $E = \frac{Δ V}{d} = \frac{10}{0.02} = 500 V / m$ .

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Two equipotential surfaces of 40 V and 50 V potential are separated by 2 cm. If the electric field present between them is uniform, then its strength is :

The correct option is D 500 V/mFor the uniform electric field , ΔV=Ed where ΔV=50−40=10 V is potential difference between the two equipotential surfaces.thus, E=ΔVd=100.02=500 V/m.

Two equipotential surfaces of $40 V$ and $50 V$ potential are separated by $2 c m$ . If the electric field present between them is uniform, then its strength is :

The correct option is D $500 V / m$
For the uniform electric field , $Δ V = E d$ where $Δ V = 50 - 40 = 10$ V is potential difference between the two equipotential surfaces.
thus, $E = \frac{Δ V}{d} = \frac{10}{0.02} = 500 V / m$ .