Two gases A and B having the same temperautre T, same pressure P and same volume V are mixed. If the temperature is at the same temperature T and occupies a volume V the pressure of the mixture is

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Solution

The correct option is A 2P
Here, initally $P_{1}$ = P
$V_{1}$ =V+V = 2V;
Finally, $P_{2}$ = P; $V_{2}$ = V
AS $P_{1} V_{1}$ = $P_{2} V_{2}$ (as inferred from equation)
$P_{2}$ = $\frac{P_{1} V_{1}}{V}$
$= \frac{P \times 2 V}{V}$
$= 2 P$

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