Two genes A and B present on same chromosome show 40% recombination, then what will be the percentage of gamete (aB) for the plant having genotype AaBb in cis arrangement?
A
40%
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B
70%
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C
20%
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D
15%
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Solution
The correct option is C20% Genotype of plant =AaBb
Number and types of gametes =(2)n=(2)2=4 AB, Ab, aB, ab. (Ab and aB are recombinant gametes).
Since, recombination =40% Hence, aB will be =20% Ab will be =20%