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Question

Two identical parallel-plate capacitors are connected in series and then joined across a battery of 100 V. A slab of dielectric constant K = 3 is inserted between the plates of the first capacitor. Then, the potential difference across the capacitors will respectively be

A
25 V, 75 V
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B
75 V, 25 V
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C
20 V, 80 V
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D
50 V, 50 V
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Solution

The correct option is A 25 V, 75 V
From given,Initially,
V1+V2=100(1) and
Q1=Q2 as they are in series.

KC.V1=CV2
3V1=V2(2)

So from (1) and (2)
V1+3V1=100
4V1=100
V1=1004=25 V
25+V2=100
V2=75 V

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