Two identical parallel plate capacitors are connected in series and then joined in series with a battery of $100 V$ . A slab of dielectric constant $K = 3$ is inserted between the plates of the first capacitor. Then, the potential difference across the capacitors will be respectively,

25 V, 75 V

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75 V, 25 V

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$20V, 780

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50 V, 50 V

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Solution

The correct option is D $25 V, 75 V$
After inserting a dielectric plate $C_{1} = 3 C a n d C_{2} = C$
$V_{1} = \frac{C \times V}{3 C + C} = \frac{C \times 100}{4 C} = 25 V, V_{2} = 100 - 25 = 75 V$

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