wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two masses A and B of 10 kg and 5 kg respectively, are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in figure, the coefficient of friction of A with the table is 0.2. The minimum mass (in kg) of C that may be placed on A to prevent it from moving is:


Open in App
Solution

Given:mA=10 kg,mB=5 kg,μ=0.2 (between block A and ground)
Since given system is in equilibrium


From FBD of block B
T=mBg=5g=50 N

For combination of block A and C
Friction force between block A and ground=μ(mA+mC)g=0.2(10+mc)g

It should be balancing tension acting on them as shown in FBD
0.2(10+mc)g=50
10+mc=25
mc=15 kg

Final Answer: 15 kg

flag
Suggest Corrections
thumbs-up
40
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon