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Question

Two masses A and B of 10Kg and 5Kg respectively are connected with a string passing over a friction less pulley fixed at the corner of a table as shown in figure. The coefficient of friction of A with the table 0.2.The minimum mass of C that may be placed on A to the prevent it from moving is equal to:
1074275_23621e5cac044419abee8c2ce5a9937d.png

A
15Kg
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B
10Kg
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C
5Kg
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D
Zero
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Solution

The correct option is A 15Kg
5g=T(i)
(10+m)μg=T(ii)
(10+m)(0.2)g=5g
5=2+0.2m
m=15Kg

976409_1074275_ans_7f4306cf7c184211929133d453fb704a.png

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