Question

Two masses $m_1$ and $m_2$ are connected by a light string passing over a smooth pulley. When set free $m_1$ moves downward by 2 m in 2s. The ratio $m_1/m_2$ is:

• A. 9/7
• B. 11/9
• C. 13/11
• D. 15/13

Answer 1

The correct option is B 11/9

$\frac{1}{2}{a}_{m_1}{t}^2=s$

$\frac{1}{2}{a}_{m_1}\ast 4=2$

$a_{m_1}=1\frac{m}{s^2}$

$\frac{[m_{1}g-m_{2}g]}{m_1+m_2}=a_{m_1}$

$\frac{\frac{m_1}{m_2}g-g}{\frac{m_1}{m_2}+1}=1$

$xg-g=x+1$

$9x=11$

$x=\frac{11}{9}$