two perfect spheres of mass 6kg and 4kg moving with velocities 6ms−1 and 4ms−1 undergo head -on-collision. Their velocities after the collision respectively in ms−1 are:
A
4 and 4
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B
4.4 and 4.4
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C
2 and −8
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D
4.4 and 4
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Solution
The correct option is C2 and −8 m1=6kg,u1=6m/s m2=4kg,u2=4m/s from conservation of me momentum and energy V1=(m1−m2m1+m2)u1+(2m2m1+m2)u2 V2=(m2−m1m1+m2)u2+(2m1m1+m2)u1 V2=4−64+6×6+4+2×64+6×6 V2=−8m/s V1=(6−46+4)×6+2×44+6×4 V1=+2m/s