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Question

Two perpendicular chords AB and CD of a circle intersect at O, (inside the circle AB is bisected at O). If AO = 4 units and OD = 6 units. Find circumradius of ΔACO.

A
13
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B
2133
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C
152
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D
2154
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Solution

The correct option is B 2133

When 2 chords intersect, the product of segment of one chord is equal to the product of segments of the other

AO×BO=OC×OD

Given AO=BO=4

4×4=OC×6

OC=83

Given AB is perpendicular to CD COA=90

AC2=OC2+OA2=649+16

AC=2083

Since AOC is a right triangle

Circumradius=12(hypotenuse)

=12×AC=2086=4136

r=2133


857210_296547_ans_40b6cb18f293486baf5152c75f8dff90.png

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